6x^2+36x-12=0

Solution for 6x^2+36x-12=0 equation:

6x^2+36x-12=0

a = 6; b = 36; c = -12;
Δ = b2-4ac
Δ = 362-4·6·(-12)
Δ = 1584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1584}=\sqrt{144*11}=\sqrt{144}*\sqrt{11}=12\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12\sqrt{11}}{2*6}=\frac{-36-12\sqrt{11}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12\sqrt{11}}{2*6}=\frac{-36+12\sqrt{11}}{12}
$